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3x^2+-10x-8/16-x^2=0
We add all the numbers together, and all the variables
2x^2-10x-8/16=0
We multiply all the terms by the denominator
2x^2*16-10x*16-8=0
Wy multiply elements
32x^2-160x-8=0
a = 32; b = -160; c = -8;
Δ = b2-4ac
Δ = -1602-4·32·(-8)
Δ = 26624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{26624}=\sqrt{1024*26}=\sqrt{1024}*\sqrt{26}=32\sqrt{26}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-160)-32\sqrt{26}}{2*32}=\frac{160-32\sqrt{26}}{64} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-160)+32\sqrt{26}}{2*32}=\frac{160+32\sqrt{26}}{64} $
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